Surface tension of a soap bubble is 2.0 × 10⁻² Nm⁻¹. Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π = 22/7]
A
0.72 × 10⁻³ J
B
5.76 × 10⁻⁴ J
C
18.48 × 10⁻⁴ J
D
9.24 × 10⁻⁴ J

Question

Surface tension of a soap bubble is 2.0 × 10⁻² Nm⁻¹. Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : [Take π = 22/7]

Accepted Answer

0.72 × 10⁻³ J

Answer

5.76 × 10⁻⁴ J

Answer

18.48 × 10⁻⁴ J

Answer

9.24 × 10⁻⁴ J

NEET Physics Work Done MCQ Question