NEET2021Physics-Projectile Motion
NEET 2021 Physics Maximum Height Calculation MCQ Question
Type: MCQ-conceptual-Hard-Class 11
A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle 'θ' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, θ, is then given by:
A
θ = cos⁻¹[(gT²)/(π²R)]^(1/2)
B
θ = cos⁻¹[(π²R)/(gT²)]^(1/2)
C
θ = sin⁻¹[(π²R)/(gT²)]^(1/2)
D
θ = sin⁻¹[(2gT²)/(π²R)]^(1/2)
Correct Answer
Option D
Detailed Explanation
The maximum height is given by H = (u²sin²θ)/(2g). Given H = 4R, and u = 2πR/T, solving gives θ = cos⁻¹[(gT²)/(π²R)]^(1/2).
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