NEET Physics Speed & Velocity MCQ Question
A car moves along a straight line with its position at time t given by x(t) = 0.08t^3. What is the average velocity of the car between t = 2.0 s and t = 4.0 s?
84 m/s
9.60 m/s
15.36 m/s
25.60 m/s
Correct Answer
Detailed Explanation
The average velocity is calculated as (x(4.0) - x(2.0)) / (4.0 - 2.0). Substituting the position function, the average velocity is [(0.084.0^3) - (0.082.0^3)] / 2 = 9.60 m/s.
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