NEET Physics Speed & Velocity MCQ Question
If a vehicle moving at 20 m/s comes to a stop with a constant deceleration, what is the stopping distance if the deceleration is 5 m/s²?
40 m
20 m
80 m
50 m
Correct Answer
Detailed Explanation
Using the equation of motion v² = v₀² + 2ax and setting v = 0, we find the stopping distance d = -v₀² / (2a) = -(20 m/s)² / (2 * -5 m/s²) = 40 m.
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