Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
An object moves along a straight line with a velocity given by v(t) = 4t + 2 m/s. What is the displacement of the object from t = 0 to t = 3 seconds?
A
21 meters
B
18 meters
C
24 meters
D
30 meters
Correct Answer
Option A
Detailed Explanation
The displacement is the area under the v-t curve from t = 0 to t = 3 seconds. Since v(t) = 4t + 2, integrate v(t) with respect to t from 0 to 3 to find displacement: ∫(4t + 2) dt from 0 to 3 = [2t^2 + 2t] from 0 to 3 = 21 meters.
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