NEET Physics Distance & Displacement MCQ Question
Consider a velocity-time graph for an object moving with uniform acceleration. If the area under the curve from time t=0 to t=T represents the displacement of the object, what can be inferred about the relationship between the initial velocity v0, final velocity v, and the displacement x?
The displacement x is equal to the area of a triangle formed by v0, v, and T.
The displacement x is equal to the area of a rectangle formed by v0 and T.
The displacement x is equal to the arithmetic average of v0 and v multiplied by time T.
The displacement x is solely determined by the final velocity v and time T.
Correct Answer
Detailed Explanation
The displacement x is given by the area under the velocity-time graph, which is the sum of the areas of a triangle and a rectangle. This can be expressed as the arithmetic average of the initial and final velocities multiplied by the time interval, as per the NCERT context.
Found an issue with this question?