Physics-Uniform Circular Motion
NEET Physics Uniform Circular Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
A stone tied to the end of a string 80 cm long is whirled in a horizontal circle at a constant speed. If the stone makes 10 revolutions per second, what is the speed of the stone?
A
50.24 m/s
B
25.12 m/s
C
5.03 m/s
D
10.06 m/s
Correct Answer
Option A
Detailed Explanation
The speed of the stone can be calculated using the formula v = 2πr/T. Given r = 0.8 m and f = 10 Hz, T = 1/f = 0.1 s, so v = 2π × 0.8 m × 10 = 50.24 m/s.
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