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Physics-Uniform Circular Motion

NEET Physics Uniform Circular Motion MCQ Question

Type: MCQ-diagram based-Hard-Class 11

Consider a diagram where an object moves in a circle of radius R with constant speed v. If the angular speed is represented by ω\omega, which of the following expressions correctly relates ω\omega with the time period of revolution TT?

Question diagram
A

ω=2πT\omega = \frac{2\pi}{T}

B

ω=vR\omega = \frac{v}{R}

C

ω=2π⋅v\omega = 2\pi \cdot v

D

ω=T2π\omega = \frac{T}{2\pi}

Correct Answer

Option A

Detailed Explanation

The angular speed ω\omega is related to the time period of revolution TT by the expression ω=2πT\omega = \frac{2\pi}{T}, as stated in the NCERT context.

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