Physics-Uniform Circular Motion
NEET Physics Uniform Circular Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A stone tied to a string is whirled in a horizontal circle of radius 0.8 m with a constant speed. If the string makes one complete revolution in 2 seconds, what is the centripetal acceleration of the stone?
A
6.32 m/s²
B
7.91 m/s²
C
9.87 m/s²
D
4.98 m/s²
Correct Answer
Option B
Detailed Explanation
Centripetal acceleration is given by a_c = v²/r. First, calculate the speed v = 2πr/T = (2π × 0.8)/2 = 2.51 m/s. Then, a_c = (2.51)²/0.8 = 7.91 m/s².
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