Physics-Projectile Motion

NEET Physics Projectile Motion MCQ Question

Type: MCQ-numerical-Medium-Class 11

A projectile is launched with an initial velocity vov_o at an angle θo\theta_o with the horizontal. If the time of flight TfT_f is 4 seconds, what is the initial vertical component of velocity voyv_{oy}? (Assume g=9.8 m/s2g = 9.8 \text{ m/s}^2)

A

9.8 m/s

B

19.6 m/s

C

39.2 m/s

D

9 m/s

Correct Answer

Option B

Detailed Explanation

The time of flight TfT_f is given by Tf=2vosinθogT_f = \frac{2v_o \sin \theta_o}{g}. Solving for voyv_{oy} using Tf=4T_f = 4 seconds and g=9.8 m/s2g = 9.8 \text{ m/s}^2, we get voy=19.6 m/sv_{oy} = 19.6 \text{ m/s}.

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