Consider a diagram showing the trajectory of a projectile launched from the origin with an initial velocity $ v_0 $ at an angle $ \theta_0 $ with the horizontal. If $ v_y $ is the vertical compo

Question

Consider a diagram showing the trajectory of a projectile launched from the origin with an initial velocity $v_0$ at an angle $\theta_0$ with the horizontal. If $v_y$ is the vertical component of velocity at a certain time $t$ , what is the time $t_m$ at which $v_y$ becomes zero?

A

$t_m = \frac{v_0 \sin \theta_0}{g}$

B

$t_m = \frac{v_0 \cos \theta_0}{g}$

C

$t_m = \frac{2v_0 \sin \theta_0}{g}$

D

$t_m = \frac{v_0 \tan \theta_0}{g}$

Accepted Answer

$ t_m = \frac{v_0 \sin \theta_0}{g} $

Answer

$ t_m = \frac{v_0 \cos \theta_0}{g} $

Answer

$ t_m = \frac{2v_0 \sin \theta_0}{g} $

Answer

$ t_m = \frac{v_0 \tan \theta_0}{g} $

NEET Physics Projectile Motion MCQ Question

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