Physics-Projectile Motion
NEET Physics Projectile Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
A projectile is launched from the ground with an initial velocity of 20 m/s at an angle of 30° with the horizontal. What is the maximum height reached by the projectile?
A
5 m
B
10 m
C
15 m
D
20 m
Correct Answer
Option B
Detailed Explanation
The maximum height is given by H = (v_0^2 * sin^2(θ)) / (2g). Here, v_0 = 20 m/s, θ = 30°, and g = 9.8 m/s². Plugging in the values, H = (20^2 * (1/2)^2) / (2 * 9.8) = 10 m.
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