Physics-Projectile Motion
NEET Physics Projectile Motion MCQ Question
Type: MCQ-diagram based-Easy-Class 11
Consider a diagram of a projectile's path shown as a parabola. What is the correct expression for the time taken by the projectile to reach its maximum height?
A
t_m = v_o sinθ_o / g
B
t_m = 2(v_o sinθ_o) / g
C
t_m = v_o cosθ_o / g
D
t_m = (v_o sinθ_o)^2 / g
Correct Answer
Option A
Detailed Explanation
The time to reach maximum height, t_m, is derived from setting the vertical velocity component to zero, giving t_m = v_o sinθ_o / g.
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