Physics-Projectile Motion
NEET Physics Projectile Motion MCQ Question
Type: MCQ-numerical-Easy-Class 11
If a projectile is launched with an initial velocity of 20 m/s at an angle of 30° with the horizontal, what is the horizontal component of its initial velocity?
A
10 m/s
B
17.32 m/s
C
20 m/s
D
11.55 m/s
Correct Answer
Option B
Detailed Explanation
The horizontal component of the initial velocity is given by v_ox = v_o * cos(θ), where v_o = 20 m/s and θ = 30°. Using cos(30°) = √3/2, v_ox = 20 * √3/2 = 17.32 m/s.
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