NEET2025Physics-Modern Physics
NEET 2025 Physics De-Broglie Wavelength MCQ Question
Type: MCQ-conceptual-Easy-Class 12
De⁻Broglie wavelength of an electron orbiting in the n = 2 state of hydrogen atom is close to (Given Bohr radius = 0.052 nₘ)
A
0.067 nₘ
B
0.67 nₘ
C
1.67 nₘ
D
2.67 nₘ
Correct Answer
Option B
Detailed Explanation
The de-Broglie wavelength λ is given by λ = h/p, where p is the momentum. For an electron in the n-th orbit, λ = 2πr/n, where r is the Bohr radius. For n = 2, λ = 2π(0.052 nₘ)/2 ≈ 0.67 nₘ.
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