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NEET 2024 Physics de Broglie Wavelength MCQ Question

Type: MCQ-conceptual-Medium-Class 12

The graph which shows the variation of $\left( \frac{1}{\lambda^2} \right)$ and its kinetic energy, E is (where $\lambda$ is de Broglie wavelength of a free particle):

Correct Answer

Option B

Detailed Explanation

The de Broglie wavelength $\lambda$ is inversely proportional to the square root of the kinetic energy $E$ . Therefore, $\frac{1}{\lambda^2}$ is directly proportional to $E$ , resulting in a linear graph passing through the origin.

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