NEET2015Physics-Modern Physics
NEET 2015 Physics Atomic Structure MCQ Question
Type: MCQ-numerical-Hard-Class 12
Consider orbit of He⁺ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 × 10⁹ constant, Z = 2 and h (Planck's Constant) = 6.6 × 10⁻³⁴ Js]
A
0.73 × 10⁶ m/s
B
3.0 × 10⁸ m/s
C
2.92 × 10⁶ m/s
D
1.46 × 10⁶ m/s
Correct Answer
Option A
Detailed Explanation
Using the formula for the speed of an electron in a hydrogen-like atom v = rac{Z e^2}{2 \epsilon_0 h n}, the speed is calculated to be 2.92 × 10⁶ m/s.
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