NEET2024Physics-Mechanics

NEET 2024 Physics Newton's Laws MCQ Question

Type: MCQ-numerical-Medium-Class 11

A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is:

Question diagram
A

6 N

B

10 N

C

zero

D

4 N

Correct Answer

Option A

Detailed Explanation

The acceleration of the system is a = F/(m₁ + m₂) = 10/(2+3) = 2 m/s². The force exerted by A on B is F = m₂a = 3 * 2 = 6 N.

Found an issue with this question?