NEET 2015 Physics Friction and Tension MCQ Question
A block A of mass m₁ rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m₂ is suspended. The coefficient of kinetic friction between the block and table is μₖ. When the block A is sliding on the table, the tension in the string is
(m₂ + μₖm₁)g / (m₁ + m₂)
(m₂ - μₖm₁)g / (m₁ + m₂)
m₁m₂(¹⁺ μₖ)g / (m₁ + m₂)
m₁m₂(¹⁻ μₖ)g / (m₁ + m₂)
Correct Answer
Detailed Explanation
The tension in the string is calculated by considering the forces acting on both blocks and the frictional force on block A. The net force on block A is (m₂ - μₖm₁)g, leading to the given expression for tension.
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