Physics-Young's Modulus
NEET Physics Young's Modulus MCQ Question
Type: MCQ-numerical-Hard-Class 11
A steel wire of length 2 m and cross-sectional area 2.5 × 10^-5 m^2 is stretched under a load of 500 N. Given that the Young's modulus of steel is 2 × 10^11 N/m^2, calculate the elongation in the wire.
A
0.005 m
B
0.001 m
C
0.002 m
D
0.0005 m
Correct Answer
Option D
Detailed Explanation
Using the formula for Young's modulus, Y = (F/A) / (ΔL/L), we can solve for ΔL: ΔL = (F * L) / (A * Y). Substituting the given values, ΔL = (500 N * 2 m) / (2.5 × 10^-5 m^2 * 2 × 10^11 N/m^2) = 0.0005 m.
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