Physics-Young's Modulus
NEET Physics Young's Modulus MCQ Question
Type: MCQ-numerical-Medium-Class 11
A steel wire with a diameter of 3.0 mm and length of 2.0 m is stretched by a force causing an elongation of 1.0 mm. If the Young's modulus for steel is 210 × 10^9 N/m², what is the force applied on the wire?
A
1485 N
B
1570 N
C
1650 N
D
1725 N
Correct Answer
Option A
Detailed Explanation
Using the formula for Young's modulus Y = (F/A) / (ΔL/L), where A is the cross-sectional area, the force F = Y × A × (ΔL/L). The area A = π × (1.5 × 10^-3 m)² and substituting the values gives F = 1485 N.
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