NEET Physics Young's Modulus MCQ Question
Imagine a diagram showing a steel rope used in a crane to lift a 10 tonne load. The rope's cross-sectional area is calculated to prevent permanent deformation. Which of the following calculations correctly determines the minimum cross-sectional area required to keep the rope within its elastic limit?
A = (10000 kg × 9.8 m/s²) / (300 × 10⁶ N/m²)
A = (10000 kg × 9.8 m/s²) / (600 × 10⁶ N/m²)
A = (5000 kg × 9.8 m/s²) / (150 × 10⁶ N/m²)
A = (10000 kg × 9.8 m/s²) / (150 × 10⁶ N/m²)
Correct Answer
Detailed Explanation
The formula A ≥ W/σ_y = Mg/σ_y calculates the minimum cross-sectional area required to prevent permanent deformation, where W is the weight, M is mass, g is acceleration due to gravity, and σ_y is the yield strength of mild steel.
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