NEET Physics Young's Modulus MCQ Question
A steel rope is used to lift a load of 5 tonnes. If the yield strength of steel is 300 x 10^6 N/m^2, what is the minimum required cross-sectional area to prevent permanent deformation?
65 x 10^-4 m^2
3 x 10^-4 m^2
6.6 x 10^-4 m^2
9.9 x 10^-4 m^2
Correct Answer
Detailed Explanation
Using the formula A ≥ Mg/σ_y, for a 5-tonne load (5000 kg) and yield strength of 300 x 10^6 N/m^2, the area A is calculated as (5000 kg x 9.8 m/s^2) / (300 x 10^6 N/m^2) = 1.65 x 10^-4 m^2.
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