NEET Physics Stress & Strain MCQ Question
A wire of original length L and cross-sectional area A is stretched by a force F, resulting in an extension of l. If the Young's modulus of the material of the wire is Y, what is the elastic potential energy stored per unit volume in the wire?
1/2 × (F/A) × (l/L)
(F × l)/(2 × L × A)
Y × (l/L)^2
1/2 × Y × (l/L)^2
Correct Answer
Detailed Explanation
The elastic potential energy per unit volume u is given by 1/2 × stress × strain. Stress is F/A and strain is l/L, so u = 1/2 × Y × (l/L)^2.
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