Physics-Stress & Strain
NEET Physics Stress & Strain MCQ Question
Type: MCQ-numerical-Hard-Class 11
A cylindrical rod of cross-sectional area 5 cm² is subjected to a tensile force of 4000 N. Calculate the stress experienced by the rod.
A
80 Pa
B
800,000 Pa
C
800 Pa
D
8,000,000 Pa
Correct Answer
Option B
Detailed Explanation
Stress is calculated as force per unit area. Using the formula stress = F/A, where F = 4000 N and A = 5 cm² = 5 × 10⁻⁴ m², gives stress = 4000 / (5 × 10⁻⁴) = 800,000 Pa.
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