Physics-Elastic Behavior
NEET Physics Elastic Behavior MCQ Question
Type: MCQ-numerical-Medium-Class 11
A steel wire is stretched by applying a force such that it reaches its elastic limit. If the cross-sectional area of the wire is 2.0 × 10^-6 m^2 and the yield strength is 300 × 10^6 N/m^2, what is the maximum force that can be applied without causing permanent deformation?
A
600 N
B
150 N
C
300 N
D
100 N
Correct Answer
Option A
Detailed Explanation
The maximum force that can be applied without causing permanent deformation is given by the yield strength multiplied by the cross-sectional area: F = σ_y × A = (300 × 10^6 N/m^2) × (2.0 × 10^-6 m^2) = 600 N.
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