NEET Physics Elastic Behavior MCQ Question
A steel wire of original length L is subjected to a tensile force F, resulting in an elongation of ΔL. If the cross-sectional area of the wire is A and the Young's modulus of steel is Y, what is the expression for the elongation ΔL?
ΔL = (F × L) / (Y × A)
ΔL = (Y × A) / (F × L)
ΔL = (F × A) / (Y × L)
ΔL = (Y × L) / (F × A)
Correct Answer
Detailed Explanation
The elongation ΔL of a material under tensile stress can be calculated using the formula ΔL = (F × L) / (Y × A), where F is the force applied, L is the original length, Y is the Young's modulus, and A is the cross-sectional area.
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