Physics-(general)

NEET Physics (general) MCQ Question

Type: MCQ-diagram based-Hard-Class 11

Consider a diagram depicting a fluid flowing through a horizontal pipe with varying cross-section, as described in the NCERT context. If P1, v1, and A1 are the pressure, velocity, and cross-sectional area at the wider section, and P2, v2, and A2 at the narrower section, what equation correctly represents the pressure difference (P1 - P2) in terms of fluid density ρ\rho and velocity change?

Question diagram
A

(P1 - P2) = 12ρ(v22v12)\frac{1}{2} \rho (v2^2 - v1^2)

B

(P1 - P2) = ρg(h2h1)\rho g (h2 - h1)

C

(P1 - P2) = ρΔV(v2v1)\rho \Delta V (v2 - v1)

D

(P1 - P2) = 12ρg(v22v12)\frac{1}{2} \rho g (v2^2 - v1^2)

Correct Answer

Option A

Detailed Explanation

The expression (P1 - P2) = 12ρ(v22v12)\frac{1}{2} \rho (v2^2 - v1^2) is derived by applying the work-energy theorem to the fluid flow, as explained in the NCERT context.

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