Physics-(general)
NEET Physics (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
A vertical capillary tube of radius 0.5 mm is inserted into an open vessel of water. Calculate the height to which water will rise in the tube. Assume the surface tension of water is 0.072 N/m and the density of water is 1000 kg/m³. Consider the contact angle to be zero and g = 9.8 m/s².
A
0.147 m
B
0.294 m
C
0.735 m
D
0.410 m
Correct Answer
Option B
Detailed Explanation
Using the formula for capillary rise h = (2T cos θ)/(ρga), where T is the surface tension, θ is the contact angle, ρ is the density, g is the acceleration due to gravity, and a is the radius. Substituting the given values, h = (2 × 0.072 × 1)/(1000 × 9.8 × 0.0005) = 0.294 m.
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