NEET 2014 Physics Coalescence of Drops MCQ Question
A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V. If ‘T’ is the surface tension of the liquid, then
Energy = 4VT (1/r - 1/R) is released
Energy = 3VT (1/r + 1/R) is absorbed
Energy = 3VT (1/r - 1/R) is released
Energy is neither released nor absorbed
Correct Answer
Detailed Explanation
When small drops coalesce to form a larger drop, the surface area decreases, releasing energy. The energy released is given by the change in surface area multiplied by the surface tension.
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