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Physics-Bernoulli's Principle

NEET Physics Bernoulli's Principle MCQ Question

Type: MCQ-numerical-Hard-Class 11

An incompressible fluid is flowing through a horizontal pipe with two sections of different cross-sectional areas. The velocity of the fluid at the first section with cross-sectional area 0.1 m² is 2 m/s. If the cross-sectional area of the second section is 0.05 m², what is the velocity of the fluid at the second section assuming steady flow?

A

1 m/s

B

2 m/s

C

4 m/s

D

8 m/s

Correct Answer

Option C

Detailed Explanation

According to the principle of continuity for incompressible fluids, A1v1 = A2v2. Here, A1 = 0.1 m², v1 = 2 m/s, A2 = 0.05 m². Solving for v2 gives v2 = (A1v1)/A2 = (0.1 m² * 2 m/s) / 0.05 m² = 4 m/s.

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