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Physics-Bernoulli's Principle

NEET Physics Bernoulli's Principle MCQ Question

Type: MCQ-numerical-Easy-Class 11

A fluid flows steadily through a horizontal pipe with varying cross-sectional area. At a point where the pipe narrows, the velocity of the fluid is 4 m/s and the pressure is 5 × 10^4 Pa. What is the pressure at a wider section of the pipe where the velocity is 2 m/s?

A

6 × 10^4 Pa

B

4 × 10^4 Pa

C

5 × 10^4 Pa

D

7 × 10^4 Pa

Correct Answer

Option A

Detailed Explanation

According to Bernoulli's Principle, in a horizontal flow with different cross-sectional areas, a decrease in velocity results in an increase in pressure. Using Bernoulli's equation: P1 + 0.5 * ρ * v1^2 = P2 + 0.5 * ρ * v2^2, with v1 = 4 m/s, v2 = 2 m/s and P1 = 5 × 10^4 Pa, we find P2 > P1.

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