NEET2018Physics-Magnetism

NEET 2018 Physics Magnetic Force on a Current-Carrying Conductor MCQ Question

Type: MCQ-numerical-Hard-Class 12

A metallic rod of mass per unit length 0.5 kg m⁻¹ is lying horizontally on a smooth inclined plane which makes an angle of 30° with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25 T is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is

A

7.14 Å

B

5.98 Å

C

14.76 Å

D

11.32 Å

Correct Answer

Option B

Detailed Explanation

Using the formula F = BIL sin θ, where F is the gravitational force component along the incline, we find the current required to balance this force.

Found an issue with this question?

Related Questions