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NEET Physics Magnetic Field due to Current MCQ Question

Type: MCQ-numerical-Medium-Class 12

As shown in the figure, a long straight conductor with semicircular arc of radius π/10 m is carrying current I = 3A. The magnitude of the magnetic field, at the center O of the arc is: (The permeability of the vacuum = 4π × 10⁻⁷ NA⁻²)

Question diagram
A

6 μT

B

2 μT

C

3 μT

D

4 μT

Correct Answer

Option A

Detailed Explanation

The magnetic field due to a semicircular arc is given by B = (μ₀I)/(4R). Substituting the given values, B = (4π × 10⁻⁷ × 3)/(4 × π/10) = 6 μT.

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