NEET2024Physics-Magnetic Coil Based
NEET 2024 Physics Magnetic Field MCQ Question
Type: MCQ-numerical-Medium-Class 12
A tightly wound 100 turns coil of radius 10 cm carries a current of 7 Å. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10⁻⁷ SI units):
A
4.4 mT
B
44 T
C
44 mT
D
4.4 T
Correct Answer
Option A
Detailed Explanation
The magnetic field at the center of a coil is given by B = (μ₀NI)/(2R). Substituting the given values, B = (4π×10⁻⁷ * 100 * 7)/(2 * 0.1) = 44 mT.
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