NEET2021Physics-Lorentz Force

NEET 2021 Physics Magnetic Field Calculation MCQ Question

Type: MCQ-numerical-Hard-Class 12

In the product F=q(v×B)\vec{F} = q (\vec{v} \times \vec{B}) = q×(i^Bi+j^Bj+k^B0)q \times (\hat{i} B_{i} + \hat{j} B_{j} + \hat{k} B_{0}) For q = 1 and v=2i^+4j^+6k^\vec{v} = 2 \hat{i} + 4 \hat{j} + 6 \hat{k} and F=4i^20j^+12k^\vec{F} = 4 \hat{i} - 20 \hat{j} + 12 \hat{k} What will be the complete expression for B\vec{B} ?

A

8i^8j^6k^-8 \hat{i} - 8 \hat{j} - 6 \hat{k}

B

6i^6j^8k^-6 \hat{i} - 6 \hat{j} - 8 \hat{k}

C

8i^+8j^6k^8 \hat{i} + 8 \hat{j} - 6 \hat{k}

D

6i^+6j^8k^6 \hat{i} + 6 \hat{j} - 8 \hat{k}

Correct Answer

Option B

Detailed Explanation

Using the cross product and given vectors, solve for B\vec{B} using F=q(v×B)\vec{F} = q (\vec{v} \times \vec{B}). The correct expression for B\vec{B} is^{-6} \hat{i} - 6 \hat{j} - 8 \hat{k}.

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