A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and g for the block

Question

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and g for the block to remain stationary on the wedge is

A

$a = \frac{g}{\csc \theta}$

B

$a = \frac{g}{\sin \theta}$

C

$a = g \cos \theta$

D

$a = g \tan \theta$

Accepted Answer

$ a = g \cos \theta $

Answer

$ a = \frac{g}{\csc \theta} $

Answer

$ a = \frac{g}{\sin \theta} $

Answer

$ a = g \tan \theta $

NEET 2018 Physics Inclined Planes MCQ Question

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