Physics-Friction
NEET Physics Friction MCQ Question
Type: MCQ-numerical-Hard-Class 11
A block of mass 5 kg is placed on a horizontal surface. The coefficient of static friction between the block and the surface is 0.4. What is the minimum horizontal force required to start moving the block?
A
20 N
B
15 N
C
25 N
D
10 N
Correct Answer
Option A
Detailed Explanation
The maximum static friction, which must be overcome to start moving the block, is calculated using the formula f_s = μ_s * N, where N = mg. Here, N = 5 kg * 9.8 m/s² = 49 N, thus f_s = 0.4 * 49 N = 19.6 N, approximately 20 N.
Found an issue with this question?