Physics-Friction

NEET Physics Friction MCQ Question

Type: MCQ-numerical-Hard-Class 11

A block of mass 5 kg is placed on a rough horizontal surface. The block is initially at rest. A horizontal force of 10 N is applied to the block. If the static friction coefficient between the block and the surface is 0.3, what is the force of friction acting on the block?

A

10 N

B

15 N

C

5 N

D

0 N

Correct Answer

Option A

Detailed Explanation

The maximum static friction force is fs=μsN=0.3×5×9.8=14.7f_s = \mu_s \cdot N = 0.3 \times 5 \times 9.8 = 14.7 N. Since the applied force (10 N) is less than fsf_s, the force of friction is equal to the applied force.

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