NEET Physics Friction MCQ Question
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of static friction between the block and the surface is 0.4, what is the maximum horizontal force that can be applied to the block before it starts to move?
20 N
15 N
25 N
10 N
Correct Answer
Detailed Explanation
The maximum static friction force is given by f_s = μ_s * N, where N = mg. Here, N = 5 kg * 9.8 m/s² = 49 N. Thus, f_s = 0.4 * 49 N = 19.6 N, which rounds to 20 N.
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