NEET Physics Equilibrium of Forces MCQ Question
A block of mass 5 kg is placed on a rough horizontal surface. It is connected to a spring scale that measures the horizontal force needed to maintain equilibrium. If the coefficient of static friction between the block and the surface is 0.4, what is the minimum force that should be applied to the block to just start moving it?
20 N
25 N
15 N
30 N
Correct Answer
Detailed Explanation
The minimum force to start moving the block is given by the static friction force, which is the product of the coefficient of static friction and the normal force. Here, the normal force is equal to the weight of the block, which is 5 kg * 9.8 m/s². Therefore, the force is 0.4 * (5 kg * 9.8 m/s²) = 19.6 N, approximately 20 N.
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