Physics-Circular Motion Dynamics

NEET Physics Circular Motion Dynamics MCQ Question

Type: MCQ-conceptual-Easy-Class 11

A car of mass m is moving in a circular path of radius R with uniform speed v. What is the expression for the maximum speed the car can have without slipping if the coefficient of static friction between the tires and the road is μs\mu_s?

A

v=μsgRv = \sqrt{\mu_s g R}

B

v=μsgRv = \sqrt{\frac{\mu_s g}{R}}

C

v=μsgRv = \sqrt{\mu_s \frac{g}{R}}

D

v=μsRgv = \sqrt{\mu_s R g}

Correct Answer

Option A

Detailed Explanation

The static friction provides the centripetal force required for circular motion. Using fsμsNf_s \leq \mu_s N and fc=mv2Rf_c = \frac{mv^2}{R}, we get vμsgRv \leq \sqrt{\mu_s g R}.

Found an issue with this question?