Physics-Orbital Motion
NEET Physics Orbital Motion MCQ Question
Type: MCQ-numerical-Hard-Class 11
If the orbital radius of Mars is 1.52 times the orbital radius of Earth, what is the ratio of the time period of Mars' orbit to Earth's orbit, based on Kepler's third law?
A
87
B
52
C
33
D
25
Correct Answer
Option A
Detailed Explanation
According to Kepler's third law, the square of the orbital period ratio is equal to the cube of the orbital radius ratio. Hence, (T_Mars / T_Earth)^2 = (1.52)^3, giving T_Mars / T_Earth = (1.52)^(3/2) ≈ 1.87.
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