Physics-Escape Velocity

NEET Physics Escape Velocity Match the Following Question

Type: Match the Following-match the column-Easy-Class 11

Match Column-I with Column-II.

Column-I Column-II (a) Minimum speed to escape Earth (i) 9.8 m/s² (b) Escape velocity formula (ii) V = √(2gR) (c) Escape velocity at surface (iii) 11.2 km/s (d) Gravitational potential energy (iv) W = -GMm/r

Choose the correct matching:

A

a-iii, b-ii, c-i, d-iv

B

a-ii, b-i, c-iii, d-iv

C

a-i, b-iii, c-iv, d-ii

D

a-iv, b-iii, c-ii, d-i

Correct Answer

Option A

Detailed Explanation

The minimum speed required for an object to escape Earth's gravitational pull is approximately 11.2 km/s (a-iii). The escape velocity formula derived from gravitational principles is V = √(2gR) (b-ii). The acceleration due to gravity at Earth's surface is about 9.8 m/s² (c-i). The gravitational potential energy expression is W = -GMm/r (d-iv).

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