NEET Physics Escape Velocity Match the Following Question
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Minimum speed to escape Earth | (i) 9.8 m/s² |
| (b) Escape velocity formula | (ii) V = √(2gR) |
| (c) Escape velocity at surface | (iii) 11.2 km/s |
| (d) Gravitational potential energy | (iv) W = -GMm/r |
a-iii, b-ii, c-i, d-iv
a-ii, b-i, c-iii, d-iv
a-i, b-iii, c-iv, d-ii
a-iv, b-iii, c-ii, d-i
Correct Answer
Detailed Explanation
The minimum speed required for an object to escape Earth's gravitational pull is approximately 11.2 km/s (a-iii). The escape velocity formula derived from gravitational principles is V = √(2gR) (b-ii). The acceleration due to gravity at Earth's surface is about 9.8 m/s² (c-i). The gravitational potential energy expression is W = -GMm/r (d-iv).
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