NEET 2021 Physics Escape Velocity MCQ Question
A particle of mass 'm' is projected with a velocity v = kVₑ(k < 1) from the surface of the earth. (Vₑ = escape velocity) The maximum height above the surface reached by the particle is:
R[(k)/(¹⁻k)]²
R[(k)/(¹⁺k)]²
R²k/(¹⁺k)
Rk²/(¹⁻k²)
Correct Answer
Detailed Explanation
The maximum height is derived from energy conservation. The kinetic energy at the surface is (1/2)mv² and potential energy at maximum height is mgh. Solving gives H = R[(k)/(¹⁻k)]².
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