NEET Physics Acceleration due to Gravity MCQ Question
If a point mass m is placed at a height h above the surface of the Earth, where h is much smaller than the Earth's radius R_E, how does the acceleration due to gravity g(h) at that height compare to the acceleration due to gravity on the surface g?
g(h) ≈ g(1 - 2h/R_E)
g(h) ≈ g(1 + 2h/R_E)
g(h) ≈ g(1 - h/R_E)
g(h) ≈ g(1 + h/R_E)
Correct Answer
Detailed Explanation
For small heights h above the surface, the acceleration due to gravity decreases by a factor of (1 - 2h/R_E) as per the binomial expansion used in the NCERT context.
Found an issue with this question?
Related Questions
More from
Assertion: The gravitational force is dominating force in nature. Reason: The Coulomb force is weaker than the gravitational force.
Match Column-I with Column-II. Column-I Column-II (a) Gravitational force between two masses (i) Proportional to the inverse square of dista...