NEET Physics Electric Force MCQ Question
The acceleration for electron and proton due to electrical force of their mutual attraction when they are 1 Å apart is
3 × 10¹⁸ m/s², 3.2 × 10¹⁶ m/s²
5 × 10²² m/s², 1.4 × 10¹⁹ m/s²
1 × 10²² m/s², 1.3 × 10¹⁹ m/s²
5 × 10¹⁸ m/s², 1.3 × 10¹⁶ m/s²
Correct Answer
Detailed Explanation
The acceleration is calculated using Coulomb's law and Newton's second law. The force is given by F = k * e² / r², and acceleration a = F/m.
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