NEET 2023 Physics Electromagnetic Waves MCQ Question
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0×10¹⁰ Hz and amplitude 48 Vm⁻¹. Then the amplitude of oscillating magnetic field is: (Speed of light in free space = 3 × 10⁸ m s⁻¹)
1.6×10⁻⁸ T
1.6×10⁻⁷ T
1.6×10⁻⁶ T
1.6×10⁻⁹ T
Correct Answer
Detailed Explanation
The amplitude of the magnetic field is given by B_0 = rac{E_0}{c}. Substituting and , we get B_0 = rac{48}{3 imes 10^8} = 1.6 imes 10^{-7} \, T.
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