NEET Physics Properties of Electromagnetic Waves MCQ Question
The magnetic field of a plane electromagnetic wave is given by: B⃗ = 2×10⁻⁸ sin(0.5×10³x + 1.5×10¹¹t)ĵT. The amplitude of the electric field would be:
6 Vm⁻¹ along x-axis
3 Vm⁻¹ along z-axis
6 Vm⁻¹ along z-axis
2 × 10⁸ Vm⁻¹ along z-axis
Correct Answer
Detailed Explanation
The amplitude of the electric field E is related to the magnetic field B by E = cB, where c is the speed of light. Here, E = 3 × 10⁸ m/s × 2 × 10⁻⁸ T = 6 Vm⁻¹.
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