NEET2014Physics-Electromagnetic Induction
NEET 2014 Physics Motional EMF MCQ Question
Type: MCQ-conceptual-Medium-Class 12
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is
A
zero
B
Bπvr²/2 and P is at higher potential
C
πrBv and R is at higher potential
D
2rBv and R is at higher potential
Correct Answer
Option C
Detailed Explanation
The potential difference is induced due to the change in magnetic flux. Using Faraday's law, the emf induced is πrBv, with R at a higher potential due to the direction of motion.
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